x^2+2x+53=0

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Solution for x^2+2x+53=0 equation:


Simplifying
x2 + 2x + 53 = 0

Reorder the terms:
53 + 2x + x2 = 0

Solving
53 + 2x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-53' to each side of the equation.
53 + 2x + -53 + x2 = 0 + -53

Reorder the terms:
53 + -53 + 2x + x2 = 0 + -53

Combine like terms: 53 + -53 = 0
0 + 2x + x2 = 0 + -53
2x + x2 = 0 + -53

Combine like terms: 0 + -53 = -53
2x + x2 = -53

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = -53 + 1

Reorder the terms:
1 + 2x + x2 = -53 + 1

Combine like terms: -53 + 1 = -52
1 + 2x + x2 = -52

Factor a perfect square on the left side:
(x + 1)(x + 1) = -52

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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